linux-检查磁盘-4k-对齐

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脚本判断磁盘分区是否4k对齐

cat check_4k_sort.sh

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#!/bin/bash
PATH=/bin:/sbin:/usr/bin:/usr/sbin
export PATH  
##osd磁盘分区8块 97表示a
##日志分区2块，106 表示j
i=106
while [ $i -lt 108 ]  # 这里会判断/dev/sdj和/dev/sdk 两块磁盘
do
j=`echo $i|awk '{printf "%c",$i}'`
echo "Start check : /dev/sd${j}"
result=`parted "/dev/sd$j" unit s print |awk '{print $2}' |awk 'NF' |grep -v 'Start' |grep -v 'Flags:' |grep -v 'DELL' |grep -v 'size' |grep -v 'Table:' |grep -v "/dev/sd$j:" |sed 's/s//g'`
array=(${result// / })
count=0
for var in ${array[@]}
do
   count=$(($count+1))
   is_4k=`expr $var / 8`
   echo $is_4k |grep "^[[:digit:]]\+$" >>/dev/null
   if [ $? -ne 0 ];then
      echo "$var is a int"
      echo "$/dev/sd$count is not 4k alignment"
   fi
done 
echo "$/dev/sd$count is 4k alignment"
i=$(($i+1))
echo -e "\n"
done